How long can the S600 be charged with more than its rated output current?

t = -17.4 * ln (1.0 - SQR(ICONT/I))

Example:
Inenn = 20 A (Typ S620)
Iist = 30 A
t = -17.4 * ln (1.0 - SQR(20/30))
t = -17.4 * ln (1.0 - 4/9)
t = -17.4 * ln (5 / 9)
t = -17.4 * (-0.587787)
t = 10.22 sec